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6(2x^2+9)=x
We move all terms to the left:
6(2x^2+9)-(x)=0
We add all the numbers together, and all the variables
-1x+6(2x^2+9)=0
We multiply parentheses
12x^2-1x+54=0
a = 12; b = -1; c = +54;
Δ = b2-4ac
Δ = -12-4·12·54
Δ = -2591
Delta is less than zero, so there is no solution for the equation
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